1832 United States presidential election in Connecticut

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1832 United States presidential election in Connecticut

← 1828 November 2 – December 5, 1832 1836 →
  Henry Clay (copy after Edward Dalton Marchant).jpg Andrew jackson head.jpg Attorney General William Wirt.jpg
Nominee Henry Clay Andrew Jackson William Wirt
Party National Republican Democratic Anti-Masonic
Home state Kentucky Tennessee Maryland
Running mate John Sergeant Martin Van Buren Amos Ellmaker
Electoral vote 8 0 0
Popular vote 18,155 11,269 3,409
Percentage 55.29% 34.32% 10.38%

The 1832 United States presidential election in Connecticut took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for president and vice president.

Connecticut voted for the National Republican candidate, Henry Clay, over the Democratic Party candidate, Andrew Jackson and the Anti-Masonic Party candidate, William Wirt. Clay won Connecticut by a margin of 20.97%.

Results[]

1832 United States presidential election in Connecticut[1]
Party Candidate Votes Percentage Electoral votes
National Republican Henry Clay 18,155 55.29% 8
Democratic Andrew Jackson 11,269 34.32% 0
Anti-Masonic William Wirt 3,409 10.38% 0
Totals 32,833 100.0% 8

See also[]

  • United States presidential elections in Connecticut

References[]

  1. ^ "1832 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved 12 April 2013.
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