1892 United States presidential election in Delaware
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![]() County Results
Cleveland 40-50% 50-60%
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Elections in Delaware |
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The 1892 United States presidential election in Delaware took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.
Delaware was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate Adlai Stevenson I of Illinois.
Results[]
1892 United States presidential election in Delaware[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Grover Cleveland | 18,581 | 49.90% | 3 | |
Republican | Benjamin Harrison (incumbent) | 18,077 | 48.55% | 0 | |
Prohibition | John Bidwell | 564 | 1.51% | 0 | |
Write-ins | Scattered | 13 | 0.03% | 0 | |
Totals | 37,235 | 100.00% | 3 | ||
Voter turnout | — |
See also[]
- United States presidential elections in Delaware
References[]
- ^ Dave Leip's U.S. Election Atlas; Presidential General Election Results – Delaware
Notes[]
Categories:
- 1892 United States presidential election by state
- United States presidential elections in Delaware
- 1892 Delaware elections