1896 United States presidential election in Delaware
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County Results
McKinley 50-60%
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Elections in Delaware |
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The 1896 United States presidential election in Delaware took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.
Delaware was won by the Republican nominees, former Ohio Governor William McKinley and his running mate Garret Hobart of New Jersey.
Results[]
1896 United States presidential election in Delaware[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Republican | William McKinley | 20,450 | 53.18% | 3 | |
Democratic | William Jennings Bryan | 16,574 | 43.10% | 0 | |
National Democratic | John M. Palmer | 966 | 2.51% | 0 | |
Prohibition | Joshua Levering | 466 | 1.21% | 0 | |
Totals | 38,456 | 100.00% | 3 | ||
Voter turnout | — |
See also[]
- United States presidential elections in Delaware
References[]
- ^ Dave Leip's U.S. Election Atlas; Presidential General Election Results – Delaware
Notes[]
Categories:
- 1896 United States presidential election by state
- United States presidential elections in Delaware
- 1896 Delaware elections