1896 United States presidential election in Delaware

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1896 United States presidential election in Delaware

← 1892 November 3, 1896 1900 →
  William McKinley by Courtney Art Studio, 1896 (cropped).jpg William Jennings Bryan 2 (cropped).jpg
Nominee William McKinley William Jennings Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Garret Hobart Arthur Sewall
Electoral vote 3 0
Popular vote 20,450 16,574
Percentage 53.18% 43.10%

Delaware Presidential Election Results 1896.svg
County Results
McKinley
  50-60%


President before election

Grover Cleveland
Democratic

Elected President

William McKinley
Republican

The 1896 United States presidential election in Delaware took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.

Delaware was won by the Republican nominees, former Ohio Governor William McKinley and his running mate Garret Hobart of New Jersey.

Results[]

1896 United States presidential election in Delaware[1]
Party Candidate Votes Percentage Electoral votes
Republican William McKinley 20,450 53.18% 3
Democratic William Jennings Bryan 16,574 43.10% 0
National Democratic John M. Palmer 966 2.51% 0
Prohibition Joshua Levering 466 1.21% 0
Totals 38,456 100.00% 3
Voter turnout

See also[]

  • United States presidential elections in Delaware

References[]

  1. ^ Dave Leip's U.S. Election Atlas; Presidential General Election Results – Delaware

Notes[]

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