1900 United States presidential election in Delaware
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County Results
McKinley 40-50% 50-60%
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Elections in Delaware |
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The 1900 United States presidential election in Delaware took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.
Delaware was won by the Republican nominees, incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York.
Results[]
1900 United States presidential election in Delaware[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Republican | William McKinley | 22,535 | 53.67% | 3 | |
Democratic | William Jennings Bryan | 18,852 | 44.90% | 0 | |
Prohibition | John Woolley | 546 | 1.30% | 0 | |
Social Democratic | Eugene Debs | 56 | 0.13% | 0 | |
Totals | 41,989 | 100.00% | 3 | ||
Voter turnout | — |
See also[]
- United States presidential elections in Delaware
References[]
- ^ Dave Leip's U.S. Election Atlas; Presidential General Election Results – Delaware
Notes[]
Categories:
- 1900 United States presidential election by state
- United States presidential elections in Delaware
- 1900 Delaware elections