1900 United States presidential election in Delaware

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1900 United States presidential election in Delaware

← 1896 November 6, 1900 1904 →
  Mckinley (cropped).jpg WilliamJBryan1902 3x4.jpg
Nominee William McKinley William Jennings Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Theodore Roosevelt Adlai Stevenson I
Electoral vote 3 0
Popular vote 22,535 18,852
Percentage 53.67% 44.90%

Delaware Presidential Election Results 1900.svg
County Results
McKinley
  40-50%
  50-60%


President before election

William McKinley
Republican

Elected President

William McKinley
Republican

The 1900 United States presidential election in Delaware took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.

Delaware was won by the Republican nominees, incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York.

Results[]

1900 United States presidential election in Delaware[1]
Party Candidate Votes Percentage Electoral votes
Republican William McKinley 22,535 53.67% 3
Democratic William Jennings Bryan 18,852 44.90% 0
Prohibition John Woolley 546 1.30% 0
Social Democratic Eugene Debs 56 0.13% 0
Totals 41,989 100.00% 3
Voter turnout

See also[]

  • United States presidential elections in Delaware

References[]

  1. ^ Dave Leip's U.S. Election Atlas; Presidential General Election Results – Delaware

Notes[]

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