1908 United States presidential election in Delaware
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![]() County Results
Taft 40-50% 50-60%
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Elections in Delaware |
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The 1908 United States presidential election in Delaware took place on November 3, 1908. All contemporary 46 states were part of the 1908 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.
Delaware was won by the Republican nominees, former Secretary of War William Howard Taft of Ohio and his running mate James S. Sherman of New York.
Results[]
1908 United States presidential election in Delaware[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Republican | William Howard Taft | 25,014 | 52.10% | 3 | |
Democratic | William Jennings Bryan | 22,055 | 45.94% | 0 | |
Prohibition | Eugene Chafin | 670 | 1.40% | 0 | |
Social Democratic | Eugene Debs | 239 | 0.50% | 0 | |
Independence | Thomas Hisgen | 29 | 0.06% | 0 | |
Totals | 48,007 | 100.00% | 3 | ||
Voter turnout | — |
See also[]
- United States presidential elections in Delaware
References[]
- ^ Dave Leip's U.S. Election Atlas; Presidential General Election Results – Delaware
Notes[]
Categories:
- 1908 United States presidential election by state
- United States presidential elections in Delaware
- 1908 Delaware elections