1908 United States presidential election in Delaware

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1908 United States presidential election in Delaware

← 1904 November 3, 1908 1912 →
  William Howard Taft, Bain bw photo portrait, 1908.jpg Unsuccessful 1908.jpg
Nominee William Howard Taft William Jennings Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate James S. Sherman John W. Kern
Electoral vote 3 0
Popular vote 25,014 22,055
Percentage 52.10% 45.94%

Delaware Presidential Election Results 1908.svg
County Results
Taft
  40-50%
  50-60%


President before election

Theodore Roosevelt
Republican

Elected President

William Howard Taft
Republican

The 1908 United States presidential election in Delaware took place on November 3, 1908. All contemporary 46 states were part of the 1908 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.

Delaware was won by the Republican nominees, former Secretary of War William Howard Taft of Ohio and his running mate James S. Sherman of New York.

Results[]

1908 United States presidential election in Delaware[1]
Party Candidate Votes Percentage Electoral votes
Republican William Howard Taft 25,014 52.10% 3
Democratic William Jennings Bryan 22,055 45.94% 0
Prohibition Eugene Chafin 670 1.40% 0
Social Democratic Eugene Debs 239 0.50% 0
Independence Thomas Hisgen 29 0.06% 0
Totals 48,007 100.00% 3
Voter turnout

See also[]

  • United States presidential elections in Delaware

References[]

  1. ^ Dave Leip's U.S. Election Atlas; Presidential General Election Results – Delaware

Notes[]

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