1920 United States presidential election in Delaware

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1920 United States presidential election in Delaware

← 1916 November 2, 1920 1924 →

Nominee Warren G. Harding James M. Cox Party Republican Democratic Home state Ohio Ohio Running mate Calvin Coolidge Franklin D. Roosevelt Electoral vote 3 0 Popular vote 52,858 39,911 Percentage 55.71% 42.07%

County Results Harding   50-60% Cox   50-60%

President before election Woodrow Wilson Democratic Elected President Warren G. Harding Republican

Elections in Delaware
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State government General elections 2010 2012 2014 2016 2018 2020 Gubernatorial elections 1792 1795 1798 1801 1804 1807 1810 1813 1816 1819 1820 (sp) 1822 (sp) 1823 (sp) 1826 1829 1832 1836 1840 1844 1846 (sp) 1850 1854 1858 1862 1866 1870 1874 1878 1882 1886 1890 1894 1896 1900 1904 1908 1912 1916 1920 1924 1928 1932 1936 1940 1944 1948 1952 1956 1960 1964 1968 1972 1976 1980 1984 1988 1992 1996 2000 2004 2008 2012 2016 2020 Lieutenant gubernatorial elections 2004 2008 2012 2016 2020 Senate elections 2018 2020 House of Representatives elections 2008 2010 2012 2014 2016 2018 2020 Special elections 10th Senate district, 2017
Wilmington Mayoral elections 2012 2016 2020
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The 1920 United States presidential election in Delaware took place on November 2, 1920. All contemporary 48 states were part of the 1920 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.

Delaware was won by the Republican nominee, Senator Warren G. Harding of Ohio, over the Democratic nominee, Governor James M. Cox of Ohio. Harding ran with Governor Calvin Coolidge of Massachusetts, while Cox ran with future President Franklin D. Roosevelt of New York.

Results[]

See also[]

• United States presidential elections in Delaware

References[]

Notes[]