1957 World Table Tennis Championships – Women's doubles

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1957 Women's doubles
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The 1957 World Table Tennis Championships women's doubles was the 23rd edition of the women's doubles championship.[1][2] Lívia Mossóczy and Agnes Simon defeated Diane Rowe and Ann Haydon in the final by three sets to two.[3]

Results[]

[2]

Round of 16 Quarterfinals Semifinals Final
Romania Ella Zeller
Romania Angelica Rozeanu
21 21 21
Netherlands
Netherlands
8 8 12 Romania Zeller
Romania Rozeanu
21 21 21
Germany
Germany
21 21 21 Germany Schlaf
Germany Fiedler
19 15 14
England Molly Jones
Netherlands
15 18 12 Romania Zeller
Romania Rozeanu
19 21 21 22 14
Hungary Lívia Mossóczy
Hungary Agnes Simon
21 21 21 Hungary Mossóczy
Hungary Simon
21 10 19 24 21
Scotland
Scotland
12 10 9 Hungary Mossóczy
Hungary Simon
21 22 11 21
Japan Taeko Namba
Japan Tomi Okawa
21 21 21 Japan Namba
Japan Okawa
16 20 21 19
England
England
6 11 6 Hungary Mossóczy
Hungary Simon
14 23 21 13 21
England Ann Haydon-Jones
England Diane Rowe
21 21 21 England Haydon-Jones
England Rowe
21 21 18 21 13
France
France
15 6 15 England Haydon-Jones
England Rowe
17 15 21 21 21
South Korea
South Korea Choi Kyung-ja
21 21 21 South Korea Wie Sang Sook
South Korea Choi Kyung-ja
21 21 9 19 15
Austria
Austria
17 7 11 England Haydon-Jones
England Rowe
21 21 21
Sweden
Sweden
21 21 21 Romania Golopenta
Scotland Elliot
14 15 11
Romania Maria Golopenta
Scotland Helen Elliot
7 17 8 Romania Golopenta
Scotland Elliot
21 15 21 21
Japan Kiiko Watanabe
Japan Fujie Eguchi
18 21 22 21 Japan Watanabe
Japan Eguchi
12 21 19 16
Hungary Éva Kóczián
Hungary Ilona Kerekes
21 13 20 16

See also[]

List of World Table Tennis Championships medalists

References[]

  1. ^ "List of Winners". All About Tennis.
  2. ^ a b "Women's doubles results" (PDF). International Table Tennis Federation. Archived from the original (PDF) on 2012-04-12.
  3. ^ Montague, Trevor (2004). A-Z of Sport, pages 699-700. The Bath Press. ISBN 0-316-72645-1.
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