1990 Atlantic 10 Conference Baseball Tournament

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1990 Atlantic 10 Conference
Baseball Tournament
Teams4
FormatFour-team double elimination
Finals site
  • Bear Stadium (Boyertown)
  • Boyertown, PA
ChampionsRutgers (4th title)
Winning coachFred Hill (3rd title)
MVPPaul Prosser (West Virginia)

The 1990 Atlantic 10 Conference Baseball Championship was held at in Boyertown, Pennsylvania from May 11–14. The double elimination tournament featured the top two regular-season finishers from both of the league's divisions. East top seed Rutgers defeated West Virginia in the title game to win the tournament for the fourth time, earning the Atlantic 10's automatic bid to the 1990 NCAA Tournament.[1]

Seeding and format[]

Each division's top teams, based on winning percentage in the 16-game regular season schedule, qualified for the field. In the opening round of the four-team double-elimination format, the East Division champion played the West Division runner-up, and vice versa.

Team W L Pct. GB Seed
East Division
Rutgers 14 2 .875
–
1E
Massachusetts 12 4 .750
2
2E
Rhode Island 6 10 .375
8
–
Temple 5 11 .313
9
–
Saint Joseph's 3 13 .188
9
–
West Division
George Washington 13 3 .813
–
1W
West Virginia 12 4 .750
1
2W
St. Bonaventure 7 9 .438
6
–
Penn State 6 10 .375
7
–
Duquesne 2 14 .125
11
–

Bracket[]

  First Round Semi-Finals Finals
                             
1E Rutgers 2  
2W West Virginia 1  
  1E Rutgers 8[a]  
  2E Massachusetts 7  
1W George Washington 0
2E Massachusetts 13  
  1E Rutgers 2 6
  2W West Virginia 11 4
2W West Virginia 11  
1W George Washington 10  
  2E Massachusetts 1
  2W West Virginia 9  
  1. ^ 14 innings.

All-Tournament[]

West Virginia's Paul Drosser was named Most Outstanding Player, while Rutgers's Darrin Kotch was named Most Outstanding Pitcher.

References[]

  1. ^ "2014 Atlantic 10 Baseball Record Book" (PDF). Atlantic10.com. Archived from the original (PDF) on July 15, 2014. Retrieved July 15, 2014.
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