1996 United States House of Representatives elections in Indiana
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All 10 Indiana seats to the United States House of Representatives | ||||||||||||||||||||||
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Elections in Indiana |
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The 1996 congressional elections in Indiana were elections for Indiana's delegation to the United States House of Representatives, which occurred along with congressional elections nationwide on November 5, 1996. Republicans held a majority of Indiana's delegation over the Democrats, 6–4. Representatives were elected using the U.S. congressional districts based on the 1990 U.S. Census.
Results[]
The following are the final results from the Secretary of State of Indiana.[1]
Overview[]
United States House of Representatives elections in Indiana, 1996[2] | |||||
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Party | Votes | Percentage | Seats | +/– | |
Republican | 1,109,066 | 52.84% | 6 | - | |
Democratic | 930,919 | 44.34% | 4 | - | |
Libertarian | 59,085 | 2.81% | 0 | - | |
Others | 7 | <0.01% | 0 | - | |
Totals | 2,099,077 | 100.00% | 10 | - |
See also[]
- United States House of Representatives elections, 1996
References[]
- ^ "United States Representative". Indiana of Secretary of State. Retrieved 2008-11-09.
- ^ "Office of the Clerk, U.S. House of Representatives".
Preceded by 1994 elections |
United States House elections in Indiana 1996 |
Succeeded by 1998 elections |
Categories:
- United States House of Representatives elections in Indiana
- 1996 United States House of Representatives elections
- 1996 Indiana elections