2016 ATP World Tour Finals – Doubles
Doubles | |
---|---|
2016 ATP World Tour Finals | |
Champions | Henri Kontinen John Peers |
Runners-up | Raven Klaasen Rajeev Ram |
Final score | 2–6, 6–1, [10–8] |
Jean-Julien Rojer and Horia Tecău were the defending champions, but they failed to qualify this year.
Henri Kontinen and John Peers won the title, defeating Raven Klaasen and Rajeev Ram in the final, 2–6, 6–1, [10–8].
Seeds[]
- Pierre-Hugues Herbert / Nicolas Mahut (round robin)
- Jamie Murray / Bruno Soares (semifinals)
- Bob Bryan / Mike Bryan (semifinals)
- Feliciano López / Marc López (round robin)
- Henri Kontinen / John Peers (champions)
- Ivan Dodig / Marcelo Melo (round robin)
- Raven Klaasen / Rajeev Ram (final)
- Treat Huey / Max Mirnyi (round robin)
Alternates[]
- Juan Sebastián Cabal / Robert Farah (Did not play)
Draw[]
Key[]
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
Finals[]
Semifinals | Final | ||||||||||||
5 | Henri Kontinen John Peers | 77 | 6 | ||||||||||
3 | Bob Bryan Mike Bryan | 62 | 4 | ||||||||||
5 | Henri Kontinen John Peers | 2 | 6 | [10] | |||||||||
7 | Raven Klaasen Rajeev Ram | 6 | 1 | [8] | |||||||||
2 | Jamie Murray Bruno Soares | 1 | 4 | ||||||||||
7 | Raven Klaasen Rajeev Ram | 6 | 6 |
Group Fleming/McEnroe[]
Herbert Mahut |
López López |
Kontinen Peers |
Klaasen Ram |
RR W–L | Set W–L | Game W–L | Standings | ||
1 | Pierre-Hugues Herbert Nicolas Mahut |
5–7, 7–5, [8–10] | 7–6(7–5), 4–6, [4–10] | 5–7, 4–6 | 0–3 | 2–6 (25%) | 32–39 (45%) | 4 | |
4 | Feliciano López Marc López |
7–5, 5–7, [10–8] | 3–6, 6–7(7–9) | 3–6, 6–7(8–10) | 1–2 | 2–5 (29%) | 31–38 (45%) | 3 | |
5 | Henri Kontinen John Peers |
6–7(5–7), 6–4, [10–4] | 6–3, 7–6(9–7) | 6–3, 6–4 | 3–0 | 6–1 (86%) | 38–27 (58%) | 1 | |
7 | Raven Klaasen Rajeev Ram |
7–5, 6–4 | 6–3, 7–6(10–8) | 3–6, 4–6 | 2–1 | 4–2 (67%) | 33–30 (52%) | 2 |
Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head records; 4. in three-players-ties, percentage of sets won, then percentage of games won, then head-to-head records; 5. ATP rankings.
Group Edberg/Jarryd[]
Murray Soares |
Bryan Bryan |
Dodig Melo |
Huey Mirnyi |
RR W–L | Set W–L | Game W–L | Standings | ||
2 | Jamie Murray Bruno Soares |
6–3, 6–4 | 6–3, 3–6, [10–6] | 6–4, 7–5 | 3–0 | 6–1 (86%) | 35–25 (58%) | 1 | |
3 | Bob Bryan Mike Bryan |
3–6, 4–6 | 7–6(7–3), 6–0 | 6–4, 6–4 | 2–1 | 4–2 (67%) | 32–26 (55%) | 2 | |
6 | Ivan Dodig Marcelo Melo |
3–6, 6–3, [6–10] | 6–7(3–7), 0–6 | 7–5, 6–4 | 1–2 | 3–4 (43%) | 28–32 (47%) | 3 | |
8 | Treat Huey Max Mirnyi |
4–6, 5–7 | 4–6, 4–6 | 5–7, 4–6 | 0–3 | 0–6 (0%) | 26–38 (41%) | 4 |
Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head records; 4. in three-players-ties, percentage of sets won, then percentage of games won, then head-to-head records; 5. ATP rankings.
References[]
Categories:
- 2016 ATP World Tour Finals