2018 Milex Open – Doubles

Doubles
2018 Milex Open
Champions	Leander Paes Miguel Ángel Reyes-Varela
Runners-up	Ariel Behar Roberto Quiroz
Final score	4–6, 6–3, [10–5]
Events
Singles Doubles
← 2017 · Milex Open · 2019 →

Juan Ignacio Londero and Luis David Martínez were the defending champions but only Londero chose to defend his title, partnering Tomás Lipovsek Puches. Londero lost in the semifinals to Leander Paes and Miguel Ángel Reyes-Varela.

Paes and Reyes-Varela won the title after defeating Ariel Behar and Roberto Quiroz 4–6, 6–3, [10–5] in the final.

Seeds[]

Draw[]

Key[]

	First Round							Quarterfinals							Semifinals							Final
	1	P Cuevas D Marrero	6	6
		G Andreozzi G Durán	3	3				1	P Cuevas D Marrero	3	7	[7]
	WC	R Cid Subervi J Hernández-Fernández	0	3				WC	H Dellien V Estrella Burgos	6	5	[10]
	WC	H Dellien V Estrella Burgos	6	6											WC	H Dellien V Estrella Burgos	3	6	[3]
	3	M Arévalo J Nedunchezhiyan	6	77												A Behar R Quiroz	6	3	[10]
	WC	J Olivares C Rodríguez	3	62				3	M Arévalo J Nedunchezhiyan	7	4	[7]
		R Dutra Silva P Lorenzi	2	6	[5]				A Behar R Quiroz	5	6	[10]
		A Behar R Quiroz	6	4	[10]																		A Behar R Quiroz	6	3	[5]
		T Lipovsek Puches JI Londero	w/o																			2	L Paes MÁ Reyes-Varela	4	6	[10]
		F Bagnis C Berlocq							T Lipovsek Puches JI Londero	65	78	[11]
		S Galdós T Monteiro	64	62				4	G Escobar F Romboli	77	66	[9]
	4	G Escobar F Romboli	77	77												T Lipovsek Puches JI Londero	4	63
		G Melzer J Melzer	6	6											2	L Paes MÁ Reyes-Varela	6	77
		A Begemann F Polášek	3	3					G Melzer J Melzer	5	67
		G Elias P Krstin	3	0				2	L Paes MÁ Reyes-Varela	7	79
	2	L Paes MÁ Reyes-Varela	6	6

References[]

• Main Draw