2018 Punta Open – Doubles

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Doubles
2018 Punta Open
ChampionsArgentina Facundo Bagnis
Uruguay Ariel Behar
Runners-upItaly Simone Bolelli
Italy Alessandro Giannessi
Final score6–2, 7–6(9–7)
Events
Singles Doubles
Punta Open · 2019 →

This was the first edition of the tournament.

Facundo Bagnis and Ariel Behar won the title after defeating Simone Bolelli and Alessandro Giannessi 6–2, 7–6(9–7) in the final.

Seeds[]

Draw[]

Key[]

  • Q = Qualifier
  • WC = Wild card
  • LL = Lucky loser
  • Alt = Alternate
  • SE = Special exempt
  • PR = Protected ranking
  • ITF = ITF entry
  • JE = Junior exempt
  • w/o = Walkover
  • r = Retired
  • d = Defaulted
First round Quarterfinals Semifinals Final
1 Argentina G Andreozzi
Brazil F de Paula
6 6
Argentina H Casanova
Argentina Juan Ignacio Galarza
4 3 1 Argentina G Andreozzi
Brazil F de Paula
6 6
WC Uruguay R Arús
Uruguay N Xiviller
2 4 Argentina A Collarini
Spain C Taberner
4 2
Argentina A Collarini
Spain C Taberner
6 6 1 Argentina G Andreozzi
Brazil F de Paula
6 5 [7]
4 Argentina F Argüello
Brazil F Romboli
6 64 [10] Italy S Bolelli
Italy A Giannessi
0 7 [10]
WC Spain D Gimeno Traver
Italy GM Moroni
4 77 [3] 4 Argentina F Argüello
Brazil F Romboli
3 3
Serbia P Krstin
Serbia M Zekić
2 5 Italy S Bolelli
Italy A Giannessi
6 6
Italy S Bolelli
Italy A Giannessi
6 7 Italy S Bolelli
Italy A Giannessi
2 67
Argentina T Lipovsek Puches
Argentina JI Londero
6 6 2 Argentina F Bagnis
Uruguay A Behar
6 79
Spain C Gómez-Herrera
Spain J Martí
4 4 Argentina T Lipovsek Puches
Argentina JI Londero
6 6
Slovakia J Kovalík
Spain B Zapata Miralles
6 77 Slovakia J Kovalík
Spain B Zapata Miralles
2 4
3 Argentina F Agamenone
Spain E López Pérez
4 65 Argentina T Lipovsek Puches
Argentina JI Londero
Uruguay M Cuevas
Bolivia H Dellien
6 6 2 Argentina F Bagnis
Uruguay A Behar
w/o
WC Argentina Patricio Heras
Uruguay S Maresca
2 3 Uruguay M Cuevas
Bolivia H Dellien
Alt Argentina MF Descotte
Argentina JP Paz
1 3 2 Argentina F Bagnis
Uruguay A Behar
w/o
2 Argentina F Bagnis
Uruguay A Behar
6 6

References[]

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