2019 BNP Paribas Primrose Bordeaux – Doubles

Doubles
2019 BNP Paribas Primrose Bordeaux
Champions	Grégoire Barrère Quentin Halys
Runners-up	Romain Arneodo Hugo Nys
Final score	6–4, 6–1
Events
Singles Doubles
← 2018 · BNP Paribas Primrose Bordeaux ·  →

Bradley Klahn and Peter Polansky were the defending champions but chose not to defend their title.^[1]

Grégoire Barrère and Quentin Halys won the title after defeating Romain Arneodo and Hugo Nys 6–4, 6–1 in the final.

Seeds[]

Draw[]

Key[]

	First round							Quarterfinals							Semifinals							Final
	1	N Mahut J Melzer	64	6	[10]
		G Mager A Pellegrino	77	4	[8]			1	N Mahut J Melzer	63	2
	WC	E Benchetrit T Lamasine	6	6				WC	E Benchetrit T Lamasine	77	1r
		D Gimeno Traver D Marrero	3	2											WC	E Benchetrit T Lamasine	3	1
	4	S Gillé D Vega Hernández	6	6												R Arneodo H Nys	6	6
	WC	G Jacq A Olivetti	4	2				4	S Gillé D Vega Hernández	62	6	[4]
		R Arneodo H Nys	6	77					R Arneodo H Nys	77	4	[10]
		J Eysseric A Šančić	3	63																			R Arneodo H Nys	4	1
		E Ymer M Ymer	2	6	[10]																		G Barrère Q Halys	6	6
	ITF	R Brancaccio K-M Maamoun	6	3	[6]				E Ymer M Ymer	2	4
	ITF	S Martos Gornés O Roca Batalla	3	77	[6]			3	M Gong Ze Zhang	6	6
	3	M Gong Ze Zhang	6	64	[10]										3	M Gong Ze Zhang	4	3
		K Coppejans Z Kolář	66	4												G Barrère Q Halys	6	6
		G Barrère Q Halys	78	6					G Barrère Q Halys	7	6
	WC	Joffrey de Schepper K de Schepper	2	3				2	J Cerretani N Monroe	5	4
	2	J Cerretani N Monroe	6	6

References[]

• Main Draw