2019 Lale Cup – Doubles

Doubles
2019 Lale Cup
Champions	Marie Bouzková Rosalie van der Hoek
Runners-up	Ilona Kremen Iryna Shymanovich
Final score	7–5, 6–7(2–7), [10–5]
Events
Singles Doubles
← 2018 · Lale Cup ·  →

Ayla Aksu and Harriet Dart were the defending champions, but both players chose not to participate.

Marie Bouzková and Rosalie van der Hoek won the title, defeating Ilona Kremen and Iryna Shymanovich in the final, 7–5, 6–7^(2–7), [10–5].^[1]

Seeds[]

Draw[]

Key[]

Draw[]

	First round							Quarterfinals							Semifinals							Final
	1	O Doroshina P Monova
		Ç Büyükakçay A Vrljić	w/o						Ç Büyükakçay A Vrljić
		G Poznikhirenko S Sharipova	7	4	[8]				M Bouzková R van der Hoek	w/o
		M Bouzková R van der Hoek	5	6	[10]											M Bouzková R van der Hoek	7	7
	3	B Cengiz J Rompies	6	6											3	B Cengiz J Rompies	5	5
	WC		3	4				3	B Cengiz J Rompies	1	6	[11]
		İ Soylu B Štefková	6	6					İ Soylu B Štefková	6	4	[9]
	WC	İ Öz M Sezer	3	3																			M Bouzková R van der Hoek	7	62	[10]
		I Kremen I Shymanovich	6	6																			I Kremen I Shymanovich	5	77	[5]
		Á Bukta	2	3					I Kremen I Shymanovich	4	6	[11]
		G Minnen P Özgen	7	6					G Minnen P Özgen	6	3	[9]
	4	V Grammatikopoulou A Raina	5	4												I Kremen I Shymanovich	66	6	[11]
		A Gasanova J Terziyska	6	77											2	R Șerban I Shinikova	78	3	[9]
		F Al-Nabhani	1	63					A Gasanova J Terziyska	6	62	[7]
	WC		0	0				2	R Șerban I Shinikova	4	77	[10]
	2	R Șerban I Shinikova	6	6

References[]

• Main Draw