Aleksei Stukalov

From Wikipedia, the free encyclopedia
Aleksei Stukalov
Aleksei Stukalov 2021.jpg
Stukalov coaching FC Ufa in 2021
Personal information
Full name Aleksei Borisovich Stukalov
Date of birth (1983-11-24) 24 November 1983 (age 38)
Place of birth Stavropol, Russian SFSR
Club information
Current team
FC Ufa (manager)
Teams managed
Years Team
2005–2007 SDYuShOR-63 Smena Moscow (academy)
2009–2015 FC Khimki (academy)
2013–2015 FC Khimki-M (assistant)
2015–2016 FC Khimki (assistant)
2016 FC Khimki-M
2016 FC Baltika Kaliningrad (assistant)
2017 FC Sokol Saratov (assistant)
2017–2018 FC Sokol Saratov
2019–2021 FC Veles Moscow
2021– FC Ufa

Aleksei Borisovich Stukalov (Russian: Алексей Борисович Стукалов; born 24 November 1983) is a Russian football coach. He is the manager of Russian Premier League club FC Ufa.

Coaching career[]

On 9 April 2021 he signed a contract with Russian Premier League club FC Ufa until the summer of 2023.[1] On his RPL coaching debut on 10 April 2021, Ufa defeated FC Akhmat Grozny 3–0.[2] In his second game on 18 April 2021, Ufa won 3–0 again, this time away against FC Spartak Moscow.

Personal life[]

His father Boris Stukalov is a football manager as well.

References[]

  1. ^ "Алексей Стукалов возглавил футбольный клуб "Уфа"!" (in Russian). FC Ufa. 9 April 2021.
  2. ^ "Ufa v Akhmat game report". Russian Premier League. 10 April 2021.

External links[]


Retrieved from ""