Baia de Aramă

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Baia de Aramă
Coat of arms of Baia de Aramă
Location in Mehedinți County
Location in Mehedinți County
Baia de Aramă is located in Romania
Baia de Aramă
Baia de Aramă
Location in Romania
Coordinates: 45°0′0″N 22°48′41″E / 45.00000°N 22.81139°E / 45.00000; 22.81139Coordinates: 45°0′0″N 22°48′41″E / 45.00000°N 22.81139°E / 45.00000; 22.81139
CountryRomania
CountyMehedinți
Government
 • Mayor (2020–2024) Ilie-Ion Tudorescu[1] (PNL)
Population
 (2011)[2]
5,349
Time zoneEET/EEST (UTC+2/+3)
Vehicle reg.MH
Historical population
YearPop.±%
1910 1,490—    
1930 1,461−1.9%
1948 1,513+3.6%
1977 4,899+223.8%
1992 5,624+14.8%
2002 5,724+1.8%
2011 5,349−6.6%
Source: Census data

Baia de Aramă is a small Romanian town located in Mehedinți County, in the historical region of Oltenia, with a population of 5,349. The river Brebina runs through the town. Some Dacian ruins can be found in the town, as well as the 17th century Baia de Aramă Monastery.

The name of the town means "copper mine", suggesting that Baia de Aramă was once a strong copper mining town. However, over the years, many of the mines in the town have closed, leaving roughly half the town unemployed.

Eight villages are administered by the town: Bratilovu, Brebina, Dealu Mare, Mărășești, Negoești, Pistrița, Stănești and Titerlești.

References[]

  1. ^ "Results of the 2020 local elections". Central Electoral Bureau. Retrieved 6 June 2021.
  2. ^ "Populaţia stabilă pe judeţe, municipii, oraşe şi localităti componenete la RPL_2011" (in Romanian). National Institute of Statistics. Retrieved 4 February 2014.


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