Lewis Island (Antarctica)

Lewis Island

Lewis Island Location in Antarctica
Geography
Location	Antarctica
Coordinates	66°6′S 134°22′E / 66.100°S 134.367°E / -66.100; 134.367Coordinates: 66°6′S 134°22′E / 66.100°S 134.367°E / -66.100; 134.367
Highest elevation	30 m (100 ft)
Administration
Administered under the Antarctic Treaty System
Demographics
Population	Uninhabited

Lewis Island is a small rocky island rising to 30 metres (100 ft), marking the east side of the entrance to Davis Bay in Antarctica. It was delineated from air photos taken by U.S. Navy Operation Highjump (1946–47) and named by the Advisory Committee on Antarctic Names for James B. Lewis, Passed Midshipman on the sloop Peacock of the U.S. Exploring Expedition (1838–42) under Charles Wilkes.^[1]

See also[]

• Lewis Island (disambiguation)

References[]

 This article incorporates public domain material from the United States Geological Survey document: "Lewis Island (Antarctica)". (content from the Geographic Names Information System)

This Wilkes Land location article is a stub. You can help Wikipedia by .

• v
• t