Meduza Island

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Meduza Island
Meduza Island is located in Antarctica
Meduza Island
Meduza Island
Location of Meduza Island
Geography
LocationAntarctica
Coordinates65°01′32″S 64°05′05″W / 65.02556°S 64.08472°W / -65.02556; -64.08472
ArchipelagoWilhelm Archipelago
Area11.9 ha (29 acres)
Length670 m (2200 ft)
Width434 m (1424 ft)
Administration
Administered under the Antarctic Treaty System
Demographics
Populationuninhabited

Meduza Island (Bulgarian: остров Медуза, romanizedostrov Meduza, IPA: [ˈɔstrof mɛˈduzɐ]) is the partly ice-covered island extending 670 m in southwest–northeast direction and 434 m in north–south direction in the Dannebrog Islands group of Wilhelm Archipelago in the Antarctic Peninsula region. Its surface area is 11.9 ha.[1]

The feature is so named because of its shape supposedly resembling a jellyfish ('meduza' in Bulgarian), and in association with other descriptive names of islands in the area.[1]

Location[]

Meduza Island is located at

 WikiMiniAtlas
65°01′32″S 64°05′05″W / 65.02556°S 64.08472°W / -65.02556; -64.08472Coordinates: 65°01′32″S 64°05′05″W / 65.02556°S 64.08472°W / -65.02556; -64.08472, which is 3.18 km southwest of Kosatka Island, 509 m west-northwest of Greblo Island, 2.33 km northwest of Rollet Island, 1.26 km east-northeast of Yastreb Island and 1.4 km southeast of Tyulen Island. British mapping in 2001.

Maps[]

See also[]

Notes[]

  1. ^ a b Meduza Island. SCAR Composite Gazetteer of Antarctica

References[]

External links[]

This article includes information from the Antarctic Place-names Commission of Bulgaria which is used with permission.


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