Reuben Township, Harlan County, Nebraska
Reuben Township | |
---|---|
![]() Location in Harlan County | |
Coordinates: 40°13′11″N 099°27′24″W / 40.21972°N 99.45667°WCoordinates: 40°13′11″N 099°27′24″W / 40.21972°N 99.45667°W | |
Country | United States |
State | Nebraska |
County | Harlan |
Area | |
• Total | 35.54 sq mi (92.04 km2) |
• Land | 35.52 sq mi (91.99 km2) |
• Water | 0.02 sq mi (0.05 km2) 0.05% |
Elevation | 2,192 ft (668 m) |
Population (2000) | |
• Total | 61 |
• Density | 1.7/sq mi (0.7/km2) |
GNIS feature ID | 0838209 |
Reuben Township is one of sixteen townships in Harlan County, Nebraska, United States. The population was 61 at the 2000 census. A 2006 estimate placed the township's population at 56.[1]
See also[]
References[]
- ^ "Subcounty population estimates: Nebraska 2000-2006". United States Census Bureau, Population Division. 2007-06-28. Archived from the original (CSV) on 2008-02-18. Retrieved 2008-02-26.
External links[]
Categories:
- Townships in Harlan County, Nebraska
- Townships in Nebraska
- South Central Nebraska geography stubs