San Francisco Huehuetlán
San Francisco Huehuetlán | |
---|---|
Municipality and town | |
![]() ![]() San Francisco Huehuetlán Location in Mexico | |
Coordinates: 18°12′N 96°57′W / 18.200°N 96.950°WCoordinates: 18°12′N 96°57′W / 18.200°N 96.950°W | |
Country | ![]() |
State | Oaxaca |
Area | |
• Total | 15.31 km2 (5.91 sq mi) |
Population (2005) | |
• Total | 1,251 |
Time zone | UTC-6 (Central Standard Time) |
• Summer (DST) | UTC-5 (Central Daylight Time) |
San Francisco Huehuetlán is a town and municipality in Oaxaca in south-western Mexico. The municipality covers an area of 15.31 km². It is part of the Teotitlán District in the north of the Cañada Region.
As of 2005, the municipality had a total population of 1251.[1]
References[]
- ^ "San Francisco Huehuetlán". Enciclopedia de los Municipios de México. Instituto Nacional para el Federalismo y el Desarrollo Municipal. Retrieved June 12, 2009.
Categories:
- Municipalities of Oaxaca
- Oaxaca geography stubs