Sherman Township, Antelope County, Nebraska

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Sherman Township
Location in Antelope County
Location in Antelope County
Coordinates: 42°23′27″N 098°14′27″W / 42.39083°N 98.24083°W / 42.39083; -98.24083Coordinates: 42°23′27″N 098°14′27″W / 42.39083°N 98.24083°W / 42.39083; -98.24083
CountryUnited States
StateNebraska
CountyAntelope
Area
 • Total35.81 sq mi (92.75 km2)
 • Land35.77 sq mi (92.65 km2)
 • Water0.04 sq mi (0.10 km2)  0.11%
Elevation
1,755 ft (535 m)
Population
 (2010)
 • Total103
 • Density3/sq mi (1.1/km2)
GNIS feature ID0838246

Sherman Township is one of twenty-four townships in Antelope County, Nebraska, United States. The population was 103 at the 2010 census.[1]

See also[]

References[]

  1. ^ "Geographic Identifiers: 2010 Demographic Profile Data (G001): Sherman township, Antelope County, Nebraska". U.S. Census Bureau, American Factfinder. Archived from the original on February 12, 2020. Retrieved June 27, 2013.

External links[]


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