Suchodół, Węgrów County
Suchodół | |
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Village | |
Suchodół | |
Coordinates: 52°19′N 21°56′E / 52.317°N 21.933°E | |
Country | Poland |
Voivodeship | Masovian |
County | Węgrów |
Gmina | Grębków |
Suchodół (Polish pronunciation: [suˈxɔduw]) is a village in the administrative district of Gmina Grębków, within Węgrów County, Masovian Voivodeship, in east-central Poland.[1] It lies approximately 6 kilometres (4 mi) north of Grębków, 11 km (7 mi) south-west of Węgrów, and 65 km (40 mi) east of Warsaw.
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Coordinates: 52°19′00″N 21°56′00″E / 52.3167°N 21.9333°E
Categories:
- Villages in Węgrów County
- Węgrów County geography stubs