Tępcz

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Tępcz
Village
Tępcz is located in Poland
Tępcz
Tępcz
Coordinates: 54°30′23″N 18°2′22″E / 54.50639°N 18.03944°E / 54.50639; 18.03944
CountryPoland Poland
VoivodeshipPomeranian
CountyWejherowo
GminaLuzino
Population
319

Tępcz [tɛmpt͡ʂ] (Kashubian: Tãpcz) is a village in the administrative district of Gmina Luzino, within Wejherowo County, Pomeranian Voivodeship, in northern Poland.[1] It lies approximately 8 kilometres (5 mi) south-west of Luzino, 18 km (11 mi) south-west of Wejherowo, and 42 km (26 mi) west of the regional capital Gdańsk.

For details of the history of the region, see History of Pomerania.

The village has a population of 319.

References[]

  1. ^ "Central Statistical Office (GUS) - TERYT (National Register of Territorial Land Apportionment Journal)" (in Polish). 2008-06-01.


Coordinates: 54°30′23″N 18°2′22″E / 54.50639°N 18.03944°E / 54.50639; 18.03944


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