Tępcz
Tępcz | |
---|---|
Village | |
![]() ![]() Tępcz | |
Coordinates: 54°30′23″N 18°2′22″E / 54.50639°N 18.03944°E | |
Country | ![]() |
Voivodeship | Pomeranian |
County | Wejherowo |
Gmina | Luzino |
Population | 319 |
Tępcz [tɛmpt͡ʂ] (Kashubian: Tãpcz) is a village in the administrative district of Gmina Luzino, within Wejherowo County, Pomeranian Voivodeship, in northern Poland.[1] It lies approximately 8 kilometres (5 mi) south-west of Luzino, 18 km (11 mi) south-west of Wejherowo, and 42 km (26 mi) west of the regional capital Gdańsk.
For details of the history of the region, see History of Pomerania.
The village has a population of 319.
References[]
Coordinates: 54°30′23″N 18°2′22″E / 54.50639°N 18.03944°E
Categories:
- Villages in Wejherowo County
- Wejherowo County geography stubs