Tsankov Island

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Tsankov Island
Tsankov Island is located in Antarctica
Tsankov Island
Tsankov Island
Location of Tsankov Island
Geography
LocationAntarctica
Coordinates65°03′58″S 64°08′38″W / 65.06611°S 64.14389°W / -65.06611; -64.14389
ArchipelagoWilhelm Archipelago
Area9.48 ha (23.4 acres)
Length625 m (2051 ft)
Width216 m (709 ft)
Administration
Administered under the Antarctic Treaty System
Demographics
Populationuninhabited

Tsankov Island (Bulgarian: Цанков остров, romanizedTsankov ostrov, IPA: [t͡sɐnˈkɔf ˈɔstrof]) is the mostly ice-covered island 625 m long in west-southwest to west-northeast direction and 216 m wide in the Dannebrog Islands group of Wilhelm Archipelago in the Antarctic Peninsula region. Its surface area is 9.48 ha.[1]

The feature is named after the dermatologist Nikolay Tsankov, participant in the 2010/11 and subsequent Bulgarian Antarctic campaigns.[1]

Location[]

Tsankov Island is located at

 WikiMiniAtlas
65°03′58″S 64°08′38″W / 65.06611°S 64.14389°W / -65.06611; -64.14389Coordinates: 65°03′58″S 64°08′38″W / 65.06611°S 64.14389°W / -65.06611; -64.14389, which is 293 m northwest of Stego Island, 175 m east of Bodloperka Island, 1.18 km southeast of Sprey Island and 1.25 km west-southwest of Taralezh Island. British mapping in 2001.

Maps[]

See also[]

Notes[]

  1. ^ a b Tsankov Island. SCAR Composite Gazetteer of Antarctica

References[]

External links[]

This article includes information from the Antarctic Place-names Commission of Bulgaria which is used with permission.


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