The 1836 United States presidential election in Connecticut took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.
Connecticut voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Connecticut by a narrow margin of 1.3%.
As a result of his win, Van Buren also became the first Democratic presidential candidate to carry Connecticut.
Results[]
1836 United States presidential election in Connecticut[1]
Party
Candidate
Votes
Percentage
Electoral votes
Democratic
Martin Van Buren
19,294
50.65%
8
Whig
William Henry Harrison
18,799
49.35%
0
Totals
38,093
100.0%
8
See also[]
United States presidential elections in Connecticut