The 1836 United States presidential election in Pennsylvania took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 30 representatives, or electors to the Electoral College, who voted for President and Vice President.
Pennsylvania voted for the Democratic candidate, Martin Van Buren, over the Whig candidate, William Henry Harrison. Van Buren won Pennsylvania by a narrow margin of 2.36%.
Results[]
1836 United States presidential election in Pennsylvania[1]
Party
Candidate
Votes
Percentage
Electoral votes
Democratic
Martin Van Buren
91,457
51.18%
30
Whig
William Henry Harrison
87,235
48.82%
0
Totals
178,692
100.0%
30
See also[]
List of United States presidential elections in Pennsylvania