1840 United States presidential election in Maryland

1840 United States presidential election in Maryland

← 1836 October 30 - December 2, 1840 1844 →

Nominee William Henry Harrison Martin Van Buren Party Whig Democratic Home state Ohio New York Running mate John Tyler none Electoral vote 10 0 Popular vote 33,528 28,752 Percentage 53.83% 46.17%

President before election Martin Van Buren Democratic Elected President William Henry Harrison Whig

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The 1840 United States presidential election in Maryland took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for President and Vice President.

Maryland voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Maryland by a margin of 7.66%.

Results[]

See also[]

• United States presidential elections in Maryland

References[]

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