1840 United States presidential election in Vermont

1840 United States presidential election in Vermont

← 1836 October 30 - December 2, 1840 1844 →

Nominee William Henry Harrison Martin Van Buren Party Whig Democratic Home state Ohio New York Running mate John Tyler none Electoral vote 7 0 Popular vote 32,445 18,009 Percentage 63.90% 35.47%

County Results Harrison   50–60%   60–70%   70–80%

President before election Martin Van Buren Democratic Elected President William Henry Harrison Whig

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The 1840 United States presidential election in Vermont took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Vermont by a margin of 28.43%.

Harrison's 28.43% margin of victory made it his strongest victory in the election while he carried 63.90% of the popular vote made Vermont his second strongest state after Kentucky.^[1]

Harrison had previously won the Green Mountain State against Van Buren four years earlier.

Results[]

See also[]

• United States presidential elections in Vermont

References[]

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