1844 United States presidential election in Vermont

1844 United States presidential election in Vermont

← 1840 November 1 - December 4, 1844 1848 →

Nominee Henry Clay James K. Polk James G. Birney Party Whig Democratic Liberty Home state Kentucky Tennessee Michigan Running mate Theodore Frelinghuysen George M. Dallas Thomas Morris Electoral vote 6 0 0 Popular vote 26,780 18,049 3,970 Percentage 54.84% 36.96% 8.13%

President before election John Tyler Independent Elected President James K. Polk Democratic

Elections in Vermont
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The 1844 United States presidential election in Vermont took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk and Liberty candidate James G. Birney. Clay won Vermont by a margin of 17.88%.

With 54.84% of the popular vote, Vermont would prove to be Henry Clay's second strongest state after Rhode Island. The Green Mountain State would also prove to be James G. Birney's third strongest state after New Hampshire and Massachusetts.^[1]

Results[]

See also[]

• United States presidential elections in Vermont

References[]

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