1876 United States presidential election in Colorado

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1876 United States presidential election in Colorado

November 7, 1876 1880 →
  President Rutherford Hayes 1870 - 1880 Restored (cropped).jpg
Nominee Rutherford B. Hayes
Party Republican
Home state Ohio
Running mate William A. Wheeler
Electoral vote 3

President before election

Ulysses S. Grant
Republican

Elected President

Rutherford B. Hayes
Republican

The 1876 United States presidential election in Colorado took place on November 7, 1876, as part of the 1876 United States presidential election. The state legislature chose three representatives, or electors to the Electoral College, who voted for president and vice president, which would be the first and only time the state would do so.

Colorado voted in its first ever presidential election, having become the 38th state on August 1 of that year. The state cast three electoral votes for the Republican candidate Rutherford B. Hayes. These electors were chosen by the Colorado General Assembly, the state legislature, rather than by popular vote,[1] the last time in American history that a state's electors were chosen without a popular vote.[2] This proved to be decisive as Hayes would win the electoral vote by a margin of one vote. Had Colorado not been a state in time for the 1876 election, Hayes would have lost the 1876 election to Democratic candidate Samuel J. Tilden.

Results[]

1876 United States presidential election in Colorado
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Rutherford B. Hayes of Ohio William A. Wheeler of New York 3 100.00%

References[]

  1. ^ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – Colorado
  2. ^ Schalit, Naomi (October 1, 2020). "Could a few state legislatures choose the next president?". The Conversation. Retrieved November 2, 2020.


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