The 1880 United States presidential election in New York took place on November 2, 1880. All contemporary 38 states were part of the 1880 United States presidential election. Voters chose 35 electors to the Electoral College, which selected the president and vice president.
New York was won by the Republican nominees, CongressmanJames A. Garfield of Ohio and his running mate former Collector of the Port of New YorkChester A. Arthur of New York. Garfield and Arthur defeated the Democratic nominees, famed Civil WarGeneralWinfield Scott Hancock of Pennsylvania and his running mate former Congressman and banker William Hayden English of Indiana.
Garfield narrowly carried New York State with 50.32% of the vote to Hancock's 48.42%, a victory margin of 1.90%. In a distant third came the Greenback Party candidate James B. Weaver with 1.12%.
New York weighed in for this election as less than 2% more Republican than the national average.
Hancock performed most strongly downstate in the New York City area, where he won New York County, Kings County, Queens County, and Richmond County. Hancock also won nearby Westchester County, and Rockland County. Garfield won much of upstate New York, including a victory in Erie County, home to the city of Buffalo, although Hancock did manage to win Albany County, home to the state capital of Albany, along with several rural upstate counties.
Results[]
1880 United States presidential election in New York[2]
Party
Candidate
Votes
Percentage
Electoral votes
Republican
James A. Garfield
555,544
50.32%
35
Democratic
Winfield Scott Hancock
534,511
48.42%
0
Greenback
James B. Weaver
12,373
1.12%
0
Prohibition
Neal S. Dow
1,517
0.14%
0
Totals
1,103,945
100.0%
35
See also[]
United States presidential elections in New York
James A. Garfield
Chester A. Arthur
References[]
^Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
0.3 pp
Elections in the United States
