1884 Rhode Island gubernatorial election

From Wikipedia, the free encyclopedia
1884 Rhode Island gubernatorial election

← 1883 April 2, 1884 1885 →
  RI Governor Augustus O Bourn.jpg No image.svg
Nominee Augustus O. Bourn Thomas W. Segar
Party Republican Democratic
Popular vote 15,936 9,592
Percentage 62.39% 37.56%

Governor before election

Augustus O. Bourn
Republican

Elected Governor

Augustus O. Bourn
Republican

The 1884 Rhode Island gubernatorial election was held on April 2, 1884. Incumbent Republican Augustus O. Bourn defeated Democratic nominee Thomas W. Segar with 62.39% of the vote.

General election[]

Candidates[]

  • Augustus O. Bourn, Republican
  • Thomas W. Segar, Democratic

Results[]

1884 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±%
Republican Augustus O. Bourn (incumbent) 15,936 62.39%
Democratic Thomas W. Segar 9,592 37.56%
Majority 6,344
Turnout
Republican hold Swing

References[]

  1. ^ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved October 16, 2020.
Retrieved from ""