The 1952 United States presidential election in Rhode Island took place on November 4, 1952, as part of the 1952 United States presidential election which was held throughout all contemporary 48 states. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.
Rhode Island voted for the Republican nominee, GeneralDwight D. Eisenhower of New York, over the Democratic nominee, former GovernorAdlai Stevenson of Illinois. Eisenhower ran with SenatorRichard Nixon of California, while Stevenson's running mate was SenatorJohn Sparkman of Alabama.
Eisenhower won Rhode Island by a very narrow margin of 1.85%. As a result of this, he became the first Republican candidate since Calvin Coolidge in 1924 to win the state.
Results[]
1952 United States presidential election in Rhode Island[2]
^"U.S. presidential election, 1952". Facts on File. Archived from the original on October 29, 2013. Retrieved October 24, 2013. Eisenhower, born in Texas, considered a resident of New York, and headquartered at the time in Paris, finally decided to run for the Republican nomination