Election in Minnesota
Main article: 1896 United States presidential election
1896 United States presidential election in Minnesota
Nominee
William McKinley
William Jennings Bryan
Party
Republican
Democratic
Home state
Ohio
Nebraska
Running mate
Garret Hobart
Arthur Sewall
Electoral vote
9
0
Popular vote
193,503
139,735
Percentage
53.77%
40.89%
County Results
McKinley
40-50%
50-60%
60-70%
70-80%
80-90%
Bryan
40-50%
50-60%
60-70%
President before election
Grover Cleveland
Democratic
Elected President
William McKinley
Republican
The 1896 United States presidential election in Minnesota took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election . Minnesota voters chose nine electors to the Electoral College , which selected the president and vice president .
Minnesota was won by the Republican nominees, former Ohio Governor William McKinley and his running mate Garret Hobart of New Jersey .
Results [ ]
1896 United States presidential election in Minnesota[1]
Party
Candidate
Votes
Percentage
Electoral votes
Republican
William McKinley
193,503
53.77%
9
Democratic
William Jennings Bryan
139,735
40.89%
0
Prohibition
Joshua Levering
4,348
1.27%
0
National Democratic
John M. Palmer
3,222
0.94%
0
Socialist Labor
Charles Matchett
954
0.28%
0
Totals
341,762
100.00%
9
Voter turnout
—
See also [ ]
United States presidential elections in Minnesota
References [ ]
Notes [ ]
State and district results of the 1896 United States presidential election
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See also
Presidential elections
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