1928 United States presidential election in West Virginia

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1928 United States presidential election in West Virginia

← 1924 November 6, 1928 1932 →
  Herbert Hoover - NARA - 532049.tif Unsuccessful 1928.jpg
Nominee Herbert Hoover Al Smith
Party Republican Democratic
Home state California New York
Running mate Charles Curtis Joseph T. Robinson
Electoral vote 8 0
Popular vote 375,551 263,784
Percentage 58.43% 41.04%

West Virginia Presidential Election Results 1928.svg
County Results

President before election

Calvin Coolidge
Republican

Elected President

Herbert Hoover
Republican

The 1928 United States presidential election in West Virginia took place on November 6, 1928, as part of the 1928 United States Presidential Election which was held throughout all contemporary 48 states. Voters chose eight representatives, or electors to the Electoral College, who voted for president and vice president.

West Virginia voted for the Republican nominee, Secretary of Commerce Herbert Hoover of California, over the Democratic nominee, Governor Alfred E. Smith of New York. Hoover's running mate was Senate Majority Leader Charles Curtis of Kansas, while Smith ran with Senator Joseph Taylor Robinson of Arkansas.

Hoover won the state by a margin of 17.39%. This was the last time that a non-incumbent Republican won West Virginia until 2000, and the last time that any Republican won Logan County until 2008.

Results[]

1928 United States presidential election in West Virginia[1]
Party Candidate Votes Percentage Electoral votes
Republican Herbert Hoover 375,551 58.43% 8
Democratic Alfred E. Smith 263,784 41.04% 0
Prohibition William F. Varney 1,703 0.26% 0
Socialist Norman Thomas 1,313 0.20% 0
Workers William Z. Foster 401 0.06% 0
N/A Write-ins 9 0.01% 0
Totals 642,752 100.00% 8

References[]

  1. ^ "1928 Presidential General Election Results - West Virginia". Dave Leip's Atlas of U.S. Presidential Elections. Retrieved 2013-08-02.
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