Election in Rhode Island
Main article: 1936 United States presidential election
1936 United States presidential election in Rhode Island
Nominee
Franklin D. Roosevelt
Alf Landon
William Lemke
Party
Democratic
Republican
Union
Home state
New York
Kansas
North Dakota
Running mate
John Nance Garner
Frank Knox
Thomas C. O'Brien
Electoral vote
4
0
0
Popular vote
165,238
125,031
19,569
Percentage
53.10%
40.18%
6.29%
County Results
Roosevelt
40-50%
50-60%
Landon
40-50%
50-60%
President before election
Franklin D. Roosevelt
Democratic
Elected President
Franklin D. Roosevelt
Democratic
The 1936 United States presidential election in Rhode Island was held on November 3, 1936. The state voters chose four electors to the Electoral College , who voted for president and vice president .
Rhode Island voted for Democratic Party candidate and incumbent President Franklin D. Roosevelt , who won the state by a margin of 12.92%.
Results [ ]
1936 United States presidential election in Rhode Island[1]
Party
Candidate
Running mate
Popular vote
Electoral vote
Count
%
Count
%
Democratic
Franklin Delano Roosevelt of New York
John Nance Garner of Texas
165,238
53.10%
4
100.00%
Republican
Alf Landon of Kansas
Frank Knox of Illinois
125,031
40.18%
0
0.00%
Union
William Lemke of North Dakota
Thomas C. O'Brien of Massachusetts
19,569
6.29%
0
0.00%
Socialist Labor
John W. Aiken of Connecticut
of New York
929
0.30%
0
0.00%
Communist
Earl Russell Browder of Kansas
James W. Ford of New York
411
0.13%
0
0.00%
Total
311,178
100.00%
4
100.00%
See also [ ]
United States presidential elections in Rhode Island
References [ ]
State and district results of the 1936 United States presidential election
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