1956 World Table Tennis Championships – Women's doubles

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1956 Women's doubles
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The 1956 World Table Tennis Championships women's doubles was the 22nd edition of the women's doubles championship.[1][2] Ella Zeller and Angelica Rozeanu defeated Kiiko Watanabe and Fujie Eguchi in the final by three sets to two.[3]

Results[]

[2]

Round of 16 Quarterfinals Semifinals Final
Romania Ella Zeller
Romania Angelica Rozeanu
21 21 21
Japan
Japan
17 13 18 Romania Zeller
Romania Rozeanu
21 21 21
India
United States
17 10 21 21 22 India Prisca
United States Robinson
10 8 13
Japan
Japan
21 21 15 14 20 Romania Zeller
Romania Rozeanu
21 21 21
Japan Shizuki Narahara
Japan
21 23 21 21 Japan Tanaka
Japan Okawa
13 14 15
China Sun Mei-Ying
China Chiu Chung-Hui
13 25 18 10 Japan Narahara
Japan Yamakawa
9 16 21 21 16
Japan Yoshiko Tanaka
Japan Tomi Okawa
21 21 21 Japan Tanaka
Japan Okawa
21 21 16 18 21
Hong Kong Lau Wai Lim
Hong Kong
16 18 4 Romania Zeller
Romania Rozeanu
21 14 21 21 21
England Ann Haydon-Jones
England Diane Rowe
21 21 21 21 Japan Watanabe
Japan Eguchi
14 21 15 19 9
Japan
Japan
12 23 16 16 England Haydon-Jones
England Rowe
23 18 21 21
Japan Taeko Namba
Japan
21 21 21 Japan Namba
Japan Tasaka
20 21 18 16
Hong Kong Baguio Wong
Hong Kong
18 13 8 England Haydon-Jones
England Rowe
21 21 13 21 16
United States Leah Neuberger
United States
21 17 21 20 21 Japan Watanabe
Japan Eguchi
23 14 21 18 21
Japan Kazuko Ito-Yamaizumi
Japan
18 21 19 22 17 United States Neuberger
United States Flam
10 9 11
Japan Kiiko Watanabe
Japan Fujie Eguchi
Japan Watanabe
Japan Eguchi
21 21 21

bye

See also[]

List of World Table Tennis Championships medalists

References[]

  1. ^ "List of Winners". All About Tennis.
  2. ^ a b "Women's doubles results" (PDF). International Table Tennis Federation. Archived from the original (PDF) on 2012-04-12.
  3. ^ Montague, Trevor (2004). A-Z of Sport, pages 699-700. The Bath Press. ISBN 0-316-72645-1.
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