Election in Rhode Island
Main article: 1960 United States presidential election
1960 United States presidential election in Rhode Island
Nominee
John F. Kennedy
Richard Nixon
Party
Democratic
Republican
Home state
Massachusetts
California
Running mate
Lyndon B. Johnson
Henry Cabot Lodge, Jr.
Electoral vote
4
0
Popular vote
258,032
147,502
Percentage
63.63%
36.36%
County Results
Kennedy
50-60%
60-70%
Nixon
50-60%
President before election
Dwight Eisenhower
Republican
Elected President
John F. Kennedy
Democratic
The 1960 United States presidential election in Rhode Island took place on November 8, 1960, as part of the 1960 United States presidential election , which was held throughout all 50 states. Voters chose four representatives, or electors to the Electoral College , who voted for president and vice president .
Rhode Island voted for the Democratic nominee, Senator John F. Kennedy of Massachusetts , over the Republican nominee, Vice President Richard Nixon of California . Kennedy ran with Senate Majority Leader Lyndon B. Johnson of Texas , while Nixon's running mate was Ambassador Henry Cabot Lodge, Jr. of Massachusetts .
Kennedy carried Rhode Island by a margin of 27.27%, making it his strongest state.
Results [ ]
1960 United States presidential election in Rhode Island[1]
Party
Candidate
Votes
Percentage
Electoral votes
Democratic
John F. Kennedy
258,032
63.63%
4
Republican
Richard Nixon
147,502
36.36%
0
Write-ins
Write-ins
1
0.01%
0
Totals
405,535
100.00%
4
By county [ ]
County
Kennedy%
Kennedy#
Nixon%
Nixon#
Others%
Others#
Providence
67.5%
189,014
32.5%
91,028
0%
0
Bristol
59.6%
11,099
40.4%
7,537
0%
0
Newport
56.8%
15,677
43.2%
11,942
0%
0
Kent
55.7%
30,662
44.3%
24,344
0%
0
Washington
47.8%
11,580
52.2%
12,651
0%
0
See also [ ]
United States presidential elections in Rhode Island
References [ ]
State and district results of the 1960 United States presidential election
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