2004 WTA Tour Championships – Doubles

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Doubles
2004 WTA Tour Championships
ChampionsRussia Nadia Petrova
United States Meghann Shaughnessy
Runners-upZimbabwe Cara Black
Australia Rennae Stubbs
Final score7–5, 6–2
Events
Singles Doubles
← 2003 · WTA Tour Championships · 2005 →
Main article: 2004 WTA Tour Championships

Virginia Ruano Pascual and Paola Suárez were the defending champions, but lost in the semifinals to Cara Black and Rennae Stubbs. Nadia Petrova and Meghann Shaughnessy won the title, defeating Cara Black and Rennae Stubbs in the final, 7–5, 6–2.[1]

Seeds[]

  1. Spain Virginia Ruano Pascual / Argentina Paola Suárez (semifinals)
  2. Russia Svetlana Kuznetsova / Russia Elena Likhovtseva (semifinals)

Draw[]

Key[]

  • Q = Qualifier
  • WC = Wild card
  • LL = Lucky loser
  • Alt = Alternate
  • SE = Special exempt
  • PR = Protected ranking
  • ITF = ITF entry
  • JE = Junior exempt
  • w/o = Walkover
  • r = Retired
  • d = Defaulted

Finals[]

Semifinals Final
          
1 Spain Virginia Ruano Pascual
Argentina Paola Suárez 		69 4  
Zimbabwe Cara Black
Australia Rennae Stubbs 		711 6  
Zimbabwe Cara Black
Australia Rennae Stubbs 		5 2  
Russia Nadia Petrova
United States Meghann Shaughnessy 		7 6  
Russia Nadia Petrova
United States Meghann Shaughnessy 		6 6  
2 Russia Svetlana Kuznetsova
Russia Elena Likhovtseva 		3 2  

References[]

  1. ^ "2004 WTA Tour Championships presented by Porsche" (PDF). WTA Tennis. Retrieved 2020-05-21.
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