2012 Swedish Open – Men's doubles

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Men's doubles
2012 Swedish Open
ChampionsSweden Robert Lindstedt
Romania Horia Tecău
Runners-upAustria Alexander Peya
Brazil Bruno Soares
Final score6–3, 7–6(7–5)
Events
Singles men women
Doubles men women
← 2011 · Swedish Open · 2013 →

Robert Lindstedt and Horia Tecău successfully defended their title by beating Alexander Peya and Bruno Soares 6–3, 7–6 in the final.

Seeds[]

Draw[]

Key[]

  • Q = Qualifier
  • WC = Wild card
  • LL = Lucky loser
  • Alt = Alternate
  • SE = Special exempt
  • PR = Protected ranking
  • ITF = ITF entry
  • JE = Junior exempt
  • w/o = Walkover
  • r = Retired
  • d = Defaulted

Draw[]

First round Quarterfinals Semifinals Final
1 Sweden R Lindstedt
Romania H Tecău
6 6  
  Finland H Heliövaara
Finland J Nieminen
4 4   1 Sweden R Lindstedt
Romania H Tecău
77 6  
  Portugal F Gil
Spain D Gimeno-Traver
2 1     Australia C Ebelthite
United Kingdom J Murray
65 3  
  Australia C Ebelthite
United Kingdom J Murray
6 6   1 Sweden R Lindstedt
Romania H Tecău
6 6  
3 Australia P Hanley
Austria J Knowle
6 6   3 Australia P Hanley
Austria J Knowle
4 3  
  France O Charroin
Ukraine D Molchanov
2 0   3 Australia P Hanley
Austria J Knowle
6 6  
  Brazil J Souza
Argentina H Zeballos
6 6     Brazil J Souza
Argentina H Zeballos
2 3  
  Italy S Bolelli
Italy A Giannessi
4 3   1 Sweden R Lindstedt
Romania H Tecău
6 77  
  Romania A Ungur
Italy F Volandri
79 6   2 Austria A Peya
Brazil B Soares
3 65  
Alt Spain R Bautista-Agut
Estonia J Zopp
67 3     Romania A Ungur
Italy F Volandri
6 6  
  Argentina F Delbonis
Spain A Ramos
6 3 [10]   Argentina F Delbonis
Spain A Ramos
3 1  
4 Sweden J Brunström
Belgium D Norman
4 6 [4]   Romania A Ungur
Italy F Volandri
2 0  
  Russia M Elgin
Kazakhstan M Kukushkin
6 6   2 Austria A Peya
Brazil B Soares
6 6  
WC Sweden F Bergevi
Sweden F Simonsson
1 2     Russia M Elgin
Kazakhstan M Kukushkin
65 5  
WC Sweden P Rosenholm
Sweden M Ryderstedt
0 2   2 Austria A Peya
Brazil B Soares
77 7  
2 Austria A Peya
Brazil B Soares
6 6  

References[]

Retrieved from ""