2017 Kunal Patel San Francisco Open – Doubles

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Doubles
2017 Kunal Patel San Francisco Open
ChampionsAustralia Matt Reid
Australia John-Patrick Smith
Runners-upChina Gong Maoxin
China Zhang Ze
Final score6–7(4–7), 7–5, [10–7]
Events
Singles Doubles
Kunal Patel San Francisco Open · 2018 →

This was the first edition of the tournament.

Matt Reid and John-Patrick Smith won the title after defeating Gong Maoxin and Zhang Ze 6–7(4–7), 7–5, [10–7] in the final.

Seeds[]

Draw[]

Key[]

  • Q = Qualifier
  • WC = Wild card
  • LL = Lucky loser
  • Alt = Alternate
  • SE = Special exempt
  • PR = Protected ranking
  • ITF = ITF entry
  • JE = Junior exempt
  • w/o = Walkover
  • r = Retired
  • d = Defaulted
First Round Quarterfinals Semifinals Final
1 Australia M Reid
Australia J-P Smith
6 6
WC United States Andre Dome
United States Max Ortiz
2 4 United States B Klahn
United States M Mmoh
4 4
United States B Klahn
United States M Mmoh
6 6 1 Australia M Reid
Australia J-P Smith
6 6
3 Ukraine D Molchanov
United States D Novikov
6 62 [5] United States A Lawson
United States H Reese
2 4
Belgium K Coppejans
Barbados D King
2 77 [10] Belgium K Coppejans
Barbados D King
64 7 [6]
WC United States Michael Elortegui
United States Q Vega
3 4 United States A Lawson
United States H Reese
77 5 [10]
United States A Lawson
United States H Reese
6 6 1 Australia M Reid
Australia J-P Smith
64 7 [10]
Italy S Caruso
Argentina M Trungelliti
6 1 [13] 2 China M Gong
China Z Zhang
77 5 [7]
United States M McDonald
United States T Sandgren
4 6 [11] Italy S Caruso
Argentina M Trungelliti
4 1
WC Hong Kong S Butts
Hong Kong Michael Kwong
1 2 4 United States S Bangoura
Indonesia C Rungkat
6 6
4 United States S Bangoura
Indonesia C Rungkat
6 6 4 United States S Bangoura
Indonesia C Rungkat
3 6 [6]
Mexico H Hach Verdugo
United States E Quigley
710 3 [10] 2 China M Gong
China Z Zhang
6 3 [10]
Republic of Ireland D O'Hare
United Kingdom J Salisbury
68 6 [7] Mexico H Hach Verdugo
United States E Quigley
2 6 [6]
2 China M Gong
China Z Zhang
6 2 [10]

References[]

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