2018 Internazionali di Tennis d'Abruzzo – Doubles

Doubles
2018 Internazionali di Tennis d'Abruzzo
Champions	Julian Ocleppo Andrea Vavassori
Runners-up	Ariel Behar Máximo González
Final score	7–6(7–5), 7–6(7–3)
Events
Singles Doubles
← 2017 · Internazionali di Tennis d'Abruzzo · 2019 →

Julian Knowle and Igor Zelenay were the defending champions but only Zelenay chose to defend his title, partnering Denys Molchanov. Zelenay lost in the semifinals to Ariel Behar and Máximo González.

Julian Ocleppo and Andrea Vavassori won the title after defeating Behar and González 7–6^(7–5), 7–6^(7–3) in the final.

Seeds[]

Draw[]

Key[]

	First round							Quarterfinals							Semifinals							Final
	1	G Durán J Salisbury	6	6
		R Junaid D Pel	4	4				1	G Durán J Salisbury	65	4
		L Broady S Clayton	2	2					K Krawietz A Mies	77	6
		K Krawietz A Mies	6	6												K Krawietz A Mies	77	5	[8]
	3	S Gillé J Vliegen	6	3	[10]										WC	J Ocleppo A Vavassori	63	7	[10]
		T Altuna Z Kolář	2	6	[3]			3	S Gillé J Vliegen	6	3	[8]
	WC	J Ocleppo A Vavassori	5	7	[10]			WC	J Ocleppo A Vavassori	4	6	[10]
		S Nagal G Oliveira	7	5	[8]																	WC	J Ocleppo A Vavassori	77	77
		R Arneodo A Hoang	6	65	[10]																	2	A Behar M González	65	63
	WC	F Baldi A Pellegrino	4	77	[8]				R Arneodo A Hoang	2	63
		M Draganja T Draganja	2	2				4	D Molchanov I Zelenay	6	77
	4	D Molchanov I Zelenay	6	6											4	D Molchanov I Zelenay	6	61	[6]
		A Motti D Vega Hernández	2	6	[11]										2	A Behar M González	4	77	[10]
		R Bemelmans T Griekspoor	6	2	[13]				R Bemelmans T Griekspoor	7	4	[5]
	WC	Andrea Del Federico D Kuzmanov	4	0				2	A Behar M González	5	6	[10]
	2	A Behar M González	6	6

References[]

• Main Draw