2018 Suzhou Ladies Open – Doubles

From Wikipedia, the free encyclopedia
Doubles
2018 Suzhou Ladies Open
ChampionsJapan Misaki Doi
Japan Nao Hibino
Runners-upThailand Luksika Kumkhum
Thailand Peangtarn Plipuech
Final score6–2, 6–3
Events
Singles Doubles
← 2017 · Suzhou Ladies Open · 2019 →

Jacqueline Cako and Nina Stojanović were the defending champions, but Stojanović chose not participate. Cako played alongside Prarthana Thombare, but lost in the quarterfinals to Guo Hanyu and Xun Fangying.

Misaki Doi and Nao Hibino won the title, defeating Luksika Kumkhum and Peangtarn Plipuech in the final, 6–2, 6–3.

Seeds[]

Draw[]

Key[]

  • Q = Qualifier
  • WC = Wild card
  • LL = Lucky loser
  • Alt = Alternate
  • SE = Special exempt
  • PR = Protected ranking
  • ITF = ITF entry
  • JE = Junior exempt
  • w/o = Walkover
  • r = Retired
  • d = Defaulted
  • SR = Special ranking

Draw[]

First round Quarterfinals Semifinals Final
1 Russia N Dzalamidze
Russia V Kudermetova
6 6
  India A Raina
United Kingdom E Webley-Smith
4 0 1 Russia N Dzalamidze
Russia V Kudermetova
6 6
WC China
China
6 4 [10] WC China
China
2 1
  China Jiaj Lu
India K Thandi
3 6 [8] 1 Russia N Dzalamidze
Russia V Kudermetova
2 6 [2]
3 China X Jiang
China Q Tang
6 7 Thailand L Kumkhum
Thailand P Plipuech
6 2 [10]
  Israel J Glushko
Australia Ar Rodionova
2 5 3 China X Jiang
China Q Tang
2 3
  Thailand L Kumkhum
Thailand P Plipuech
6 6 Thailand L Kumkhum
Thailand P Plipuech
6 6
WC China X Sun
China
0 3 Thailand L Kumkhum
Thailand P Plipuech
2 3
  China H Guo
China F Xun
6 6 2 Japan M Doi
Japan N Hibino
6 6
  China Q Ye
China Yi Zhang
4 2 China H Guo
China F Xun
6 64 [10]
WC China
China
1 0 4 United States J Cako
India P Thombare
4 77 [8]
4 United States J Cako
India P Thombare
6 6 China H Guo
China F Xun
4 1
  Hong Kong K-y Ng
China S Zheng
3 4 2 Japan M Doi
Japan N Hibino
6 6
  China S Feng
China J Kang
6 6 China S Feng
China J Kang
4 2
  Chinese Taipei S-y Hsieh
China X You
3 3 2 Japan M Doi
Japan N Hibino
6 6
2 Japan M Doi
Japan N Hibino
6 6

References[]

Retrieved from ""