2019 Ilkley Trophy – Women's doubles

Women's doubles
2019 Ilkley Trophy
Champions	Beatriz Haddad Maia Luisa Stefani
Runners-up	Ellen Perez Arina Rodionova
Final score	6–4, 6–7(5–7), [10–4]
Events
Singles men women Doubles men women
← 2018 · Ilkley Trophy ·  →

Asia Muhammad and Maria Sanchez were the defending champions, but lost in the semifinals to Ellen Perez and Arina Rodionova.^[1]

Beatriz Haddad Maia and Luisa Stefani won the title, defeating Perez and Rodionova 6–4, 6–7^(5–7), [10–4], in the final.

Seeds[]

Draw[]

Key[]

Draw[]

	First round							Quarterfinals							Semifinals							Final
	1	I-C Begu M Niculescu	4	6	[11]
		L Kerkhove W Osuigwe	6	4	[9]			1	I-C Begu M Niculescu
	WC	N Bains M Lumsden	3	6	[7]				B Haddad Maia L Stefani	w/o
		B Haddad Maia L Stefani	6	2	[10]											B Haddad Maia L Stefani	77	6
	4	A Blinkova S Peng	6	6											4	A Blinkova S Peng	64	3
		N Hibino Y Wickmayer	4	2				4	A Blinkova S Peng	w/o
		S Fichman V Savinykh	3	2					Y Duan L Zhu
		Y Duan L Zhu	6	6																			B Haddad Maia L Stefani	6	65	[10]
		X Jiang Q Tang	62	3																		3	E Perez Ar Rodionova	4	77	[4]
		C Lister C Perrin	77	6					C Lister C Perrin	5	0
		C Dolehide E Shibahara	1	3				3	E Perez Ar Rodionova	7	6
	3	E Perez Ar Rodionova	6	6											3	E Perez Ar Rodionova	6	64	[10]
		O Danilović I Jorović	4	6	[4]										2	A Muhammad M Sanchez	2	77	[7]
		M Brengle I Neel	6	4	[10]				M Brengle I Neel	4	64
	WC	O Nicholls K Swan	6	4	[8]			2	A Muhammad M Sanchez	6	77
	2	A Muhammad M Sanchez	2	6	[10]

References[]

• Main Draw