2019 Kobe Challenger – Doubles
Doubles | |
---|---|
2019 Kobe Challenger | |
Champions | Purav Raja Ramkumar Ramanathan |
Runners-up | André Göransson Christopher Rungkat |
Final score | 7–6(8–6), 6–3 |
Gonçalo Oliveira and Akira Santillan were the defending champions[1] but chose to defend their title with different partners. Oliveira partnered Brydan Klein but withdrew in the first round. Santillan partnered Bradley Mousley but lost in the first round to Nam Ji-sung and Song Min-kyu.
Purav Raja and Ramkumar Ramanathan won the title after defeating André Göransson and Christopher Rungkat 7–6(8–6), 6–3 in the final.
Seeds[]
- Matt Reid / Luke Saville (Quarterfinals)
- André Göransson / Christopher Rungkat (Final)
- Hsieh Cheng-peng / Yang Tsung-hua (Quarterfinals)
- Purav Raja / Ramkumar Ramanathan (Champions)
Draw[]
Key[]
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
First Round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | M Reid L Saville | 0 | 6 | [9] | |||||||||||||||||||||||
WC | Taisei Ichikawa Seita Watanabe | 6 | 5 | [4] | T Matsui Yo Watanuki | 6 | 4 | [11] | |||||||||||||||||||
T Matsui Yo Watanuki | 3 | 7 | [10] | T Matsui Yo Watanuki | 3 | 4 | |||||||||||||||||||||
4 | P Raja R Ramanathan | 4 | 4 | P Raja R Ramanathan | 6 | 6 | |||||||||||||||||||||
Sa Ratiwatana So Ratiwatana | 2r | 4 | P Raja R Ramanathan | 7 | 2 | [10] | |||||||||||||||||||||
J-s Nam M-k Song | 6 | 3 | [10] | J-s Nam M-k Song | 5 | 6 | [7] | ||||||||||||||||||||
B Mousley A Santillan | 4 | 6 | [7] | 4 | P Raja R Ramanathan | 78 | 6 | ||||||||||||||||||||
Y Bai Z Li | 77 | 6 | 2 | A Göransson C Rungkat | 66 | 3 | |||||||||||||||||||||
WC | Shintaro Imai T Niki | 61 | 4 | Y Bai Z Li | 7 | 6 | |||||||||||||||||||||
WC | Shinji Hazawa Y Shimizu | 3 | C-p Hsieh T-h Yang | 5 | 3 | ||||||||||||||||||||||
3 | C-p Hsieh T-h Yang | w/o | Y Bai Z Li | 2 | 0 | ||||||||||||||||||||||
B Klein G Oliveira | 2 | A Göransson C Rungkat | 6 | 6 | |||||||||||||||||||||||
A Kadhe E López Pérez | w/o | A Kadhe E López Pérez | 4 | 2 | |||||||||||||||||||||||
C-h Tseng T-l Wu | 4 | 3 | 2 | A Göransson C Rungkat | 6 | 6 | |||||||||||||||||||||
2 | A Göransson C Rungkat | 6 | 6 |
References[]
Categories:
- 2019 ATP Challenger Tour
- Kobe Challenger