2019 OEC Taipei WTA Challenger – Doubles

Doubles
2019 OEC Taipei WTA Challenger
Champions	Lee Ya-hsuan Wu Fang-hsien
Runners-up	Dalila Jakupović Danka Kovinić
Final score	4–6, 6–4, [10–7]
Events
Singles Doubles
← 2018 · OEC Taipei WTA Challenger ·  →

Ankita Raina and Karman Thandi were the defending champions^[1] but Thandi chose not to participate. Raina partnered alongside Bibiane Schoofs, but lost in the quarterfinals to Lee Ya-hsuan and Wu Fang-hsien.

Lee and Wu went on to win the title, defeating Dalila Jakupović and Danka Kovinić in the final, 4–6, 6–4, [10–7].

Seeds[]

Draw[]

Key[]

Draw[]

	First round							Quarterfinals							Semifinals							Final
	1	Ar Rodionova S Sanders	6	6
		E Chong A Sutjiadi	2	2				1	Ar Rodionova S Sanders	6	6
		N Dzalamidze K Rakhimova	6	6					N Dzalamidze K Rakhimova	3	3
		C-w Hsu	4	3											1	Ar Rodionova S Sanders	3	4
	3	A Raina B Schoofs	6	77												Ya-hsu Lee F-h Wu	6	6
		S Bandecchi	4	64				3	A Raina B Schoofs	6	3	[9]
		Ya-hsu Lee F-h Wu	6	6					Ya-hsu Lee F-h Wu	3	6	[11]
	WC	Y-y Yang	3	0																			Ya-hsu Lee F-h Wu	4	6	[10]
		I Shinikova P Thombare	7	6																		2	D Jakupović D Kovinić	6	4	[7]
			5	3					I Shinikova P Thombare	3	4
		I-h Cho	6	3					I-h Cho	6	6
	4	Y Sizikova E Webley-Smith	1	0r												I-h Cho	4	4
		N Bains A Hesse	6	6											2	D Jakupović D Kovinić	6	6
		P-h Chen Y-c Hsieh	3	4					N Bains A Hesse	65	4
		K Okamura P Plipuech	6	65	[7]			2	D Jakupović D Kovinić	77	6
	2	D Jakupović D Kovinić	2	77	[10]

References[]

• Main Draw