2019 Surbiton Trophy – Women's doubles

Women's doubles
2019 Surbiton Trophy
Champions	Jennifer Brady Caroline Dolehide
Runners-up	Heather Watson Yanina Wickmayer
Final score	6–3, 6–4
Events
Singles men women Doubles men women
← 2018 · Surbiton Trophy ·  →

Jessica Moore and Ellen Perez were the defending champions, but chose to participate with different partners. Moore partnered alongside Monique Adamczak but lost in the first round to Viktorija Golubic and Ingrid Neel. Perez partnered alongside Arina Rodionova but lost in the first round to Naiktha Bains and Naomi Broady.^[1]

Jennifer Brady and Caroline Dolehide won the title, defeating Heather Watson and Yanina Wickmayer in the final, 6–3, 6–4.

Seeds[]

Draw[]

Key[]

Draw[]

	First round							Quarterfinals							Semifinals							Final
	1	A Muhammad G Olmos	3	77	[10]
		S Santamaria L Stefani	6	65	[6]			1	A Muhammad G Olmos	63	3
		J Brady C Dolehide	6	6					J Brady C Dolehide	77	6
	WC	SB Grey E Silva	4	4												J Brady C Dolehide	6	6
	3	A Blinkova O Kalashnikova	3	63												M Brengle S Vickery	2	2
		M Brengle S Vickery	6	77					M Brengle S Vickery	w/o
		A Guarachi E Routliffe	64	6	[4]			WC	K Dunne E Webley-Smith
	WC	K Dunne E Webley-Smith	77	2	[10]																		J Brady C Dolehide	6	6
		H Watson Y Wickmayer	6	5	[10]																		H Watson Y Wickmayer	3	4
		Q Gleason M Sanchez	3	7	[5]				H Watson Y Wickmayer	6	3	[10]
	WC	N Bains N Broady	6	6				WC	N Bains N Broady	4	6	[8]
	4	E Perez Ar Rodionova	4	1												H Watson Y Wickmayer	4	6	[11]
		M Kato L Zhu	2	3												I Jorović T Smitková	6	3	[9]
		I Jorović T Smitková	6	6					I Jorović T Smitková	77	6
		V Golubic I Neel	2	6	[10]				V Golubic I Neel	65	4
	2	M Adamczak J Moore	6	3	[7]

References[]

• Main Draw