Cloverdale, Iowa
Cloverdale, Iowa | |
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  Cloverdale, Iowa Location of Cloverdale, Iowa | |
| Coordinates: 43°20′49″N 95°41′09″W / 43.3469151°N 95.6858470°WCoordinates: 43°20′49″N 95°41′09″W / 43.3469151°N 95.6858470°W | |
| Country |  United States |
| State |  Iowa |
| County | Osceola County |
| Elevation | 466 m (1,529 ft) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| Zip code | 51249 |
| Area code(s) | 712 |
| GNIS feature ID | 455489 |
Cloverdale is an unincorporated community in Osceola County, Iowa, United States.[1] It is located 5 miles southeast of the county seat Sibley, and 10 miles from the Iowa-Minnesota border. [2]
History[]
Cloverdale's population was 50 in 1925.[3]
References[]
- ^ "Report for: Cloverdale". USGNIS. Retrieved 16 October 2017.
- ^ "Osceola County Zoning Map" (PDF). osceolacountyia.org. Retrieved 16 October 2017.
- ^ Company, Rand McNally and (1925). Premier Atlas of the World: Containing Maps of All Countries of the World, with the Most Recent Boundary Decisions, and Maps of All the States,territories, and Possessions of the United States with Population Figures from the Latest Official Census Reports, Also Data of Interest Concerning International and Domestic Political Questions. Rand McNally & Company. p. 190.
Municipalities and communities of Osceola County, Iowa, United States | ||
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| Cities |  | |
| Townships | ||
| Unincorporated communities | ||
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Categories:
- Unincorporated communities in Osceola County, Iowa
- Unincorporated communities in Iowa