Hobart Township, Lake County, Indiana
Hobart Township | |
|---|---|
 | |
| Coordinates: 41°32′48″N 87°15′53″W / 41.54667°N 87.26472°WCoordinates: 41°32′48″N 87°15′53″W / 41.54667°N 87.26472°W | |
| Country | United States |
| State | Indiana |
| County | Lake |
| Government | |
| • Type | Indiana township |
| Area | |
| • Total | 25.98 sq mi (67.3 km2) |
| • Land | 25.47 sq mi (66.0 km2) |
| • Water | 0.51 sq mi (1.3 km2) |
| Elevation | 627 ft (191 m) |
| Population (2010) | |
| • Total | 39,417 |
| • Density | 1,547.4/sq mi (597.5/km2) |
| FIPS code | 18-34132[2] |
| GNIS feature ID | 453414 |
Hobart Township is one of eleven townships in Lake County, Indiana. As of the 2010 census, its population was 39,417 and it contained 16,366 housing units.[3]
Geography[]
According to the 2010 census, the township has a total area of 25.98 square miles (67.3 km2), of which 25.47 square miles (66.0 km2) (or 98.04%) is land and 0.51 square miles (1.3 km2) (or 1.96%) is water.[3]
References[]
- ^ "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
- ^ "U.S. Census website". United States Census Bureau. Retrieved 2008-01-31.
- ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on 2020-02-12. Retrieved 2013-05-10.
External links[]
Municipalities and communities of Lake County, Indiana, United States | ||
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| Cities |  | |
| Towns | ||
| Townships | ||
| CDPs | ||
| Other unincorporated communities | ||
| Ghost town | ||
| Footnotes | ‡This populated place also has portions in an adjacent county or counties. | |
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Categories:
- Townships in Lake County, Indiana
- Townships in Indiana
- Northwest Indiana geography stubs