Jacksonburg, West Virginia

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Jacksonburg
Census-designated place (CDP)
Jacksonburg is located in West Virginia
Jacksonburg
Jacksonburg
Location within the state of West Virginia
Coordinates: 39°31′56″N 80°38′30″W / 39.53222°N 80.64167°W / 39.53222; -80.64167Coordinates: 39°31′56″N 80°38′30″W / 39.53222°N 80.64167°W / 39.53222; -80.64167
CountryUnited States
StateWest Virginia
CountyWetzel
Area
[1]
 • Total1.501 sq mi (3.89 km2)
 • Land1.481 sq mi (3.84 km2)
 • Water0.020 sq mi (0.05 km2)
Population
 (2010)[2]
 • Total182
 • Density120/sq mi (47/km2)
Time zoneUTC-5 (Eastern (EST))
 • Summer (DST)UTC-4 (EDT)

Jacksonburg is a census-designated place (CDP) in Wetzel County, West Virginia, United States. It lies at an elevation of 748 feet (228 m).[3] As of the 2010 census, its population was 182.[2]

References[]

  1. ^ "US Gazetteer files: 2010, 2000, and 1990". United States Census Bureau. 2011-02-12. Retrieved 2011-04-23.
  2. ^ a b "U.S. Census website". United States Census Bureau. Retrieved 2011-05-14.
  3. ^ U.S. Geological Survey Geographic Names Information System: Jacksonburg, West Virginia


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